When transferring to the gas the amount of heat equal to 35 kJ, the gas performed

When transferring to the gas the amount of heat equal to 35 kJ, the gas performed work equal to 20 kJ. What is the change in the internal energy of this gas?

Data: Q (heat transferred to a given gas) = 35 kJ; A ‘(work done by gas) = 20 kJ.

To determine the desired change in the internal energy of the taken gas, we apply the first law of thermodynamics: ΔU = Q – A ‘.

Let’s calculate: ΔU = 35 – 20 ‘= 15 kJ.

Answer: The taken gas increased its internal energy by 15 kJ.