When two bodies interact, the ratio of the moduli of their accelerations is a2 \ a1 = 4

When two bodies interact, the ratio of the moduli of their accelerations is a2 \ a1 = 4, which is equal to the mass of another body if the mass of the first one is m1 = 6kg.

Given:

a2 / a1 = 4 is the ratio of the moduli of the accelerations of two bodies obtained as a result of interaction;

m1 = 6 kilograms – the mass of the first body.

It is required to determine m2 (kilogram) – the mass of the second body.

To determine the mass of the second body, you must use the following formula (Newton’s third law):

F1 = F2

m1 * a1 = m2 * a2;

m2 = m1 * a1 / a2.

Since by the condition of the problem a2 / a1 = 4, from this we obtain that a2 = 4 * a1. Then:

m2 = m1 * a1 / a2 = m1 * a1 / (4 * a1) = m1 / 4 = 6/4 = 1.5 kilograms.

Answer: the mass of the second body is 1.5 kilograms.



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