When two resistances 4.6 Ohm and 10 Ohm were connected in parallel to the 220 V network, a current arose

univerkov | September 4, 2021 | education

When two resistances 4.6 Ohm and 10 Ohm were connected in parallel to the 220 V network, a current arose. Determine the total amperage and current at each resistance.

Data: U (mains voltage) = 220 V; R1 (first specified resistance) = 4.6 ohms; R2 (second set resistance) = 10 ohms; parallel connection.

1) Total resistance: R = R1 * R2 / (R1 + R2) = 4.6 * 10 / (4.6 + 10) = 3.15 Ohm.

2) Total current strength: I = U / R = 220 / 3.15 = 69.8 A.

3) Current at the first resistance: I1 = U / R1 = 220 / 4.6 = 47.8 A.

4) Current at the second resistance: I2 = U / R2 = 220/10 = 22 A.

Check: I = I1 + I2 = 47.8 + 22 = 69.8 A (correct).

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