When weighing a body in air with a dynamometer, it shows 4.4 N, and in water – 1.6 N.

When weighing a body in air with a dynamometer, it shows 4.4 N, and in water – 1.6 N. Determine the volume of the body.

Given:

P1 = 4.4 Newton – body weight in air;

P2 = 1.6 Newton – body weight in water;

g = 10 m / s2 – acceleration of gravity (constant value near the surface of the earth);

ro = 1000 kg / m3 – water density.

It is required to determine V (m3) – body volume.

Let’s find the Archimedean (buoyancy) force acting on the body:

Farch = P1 – P2 = 4.4 – 1.6 = 2.8 Newton.

Then the volume of the body will be equal to:

V = Farch / (ro * g) = 2.8 / (1000 * 9.8) = 2.8 / 9800 = 0.00029 m3 (0.29 liters).

Answer: the volume of the body is 0.00029 cubic meters (0.29 liters).