When zinc dissolves in hydrochloric acid, 13.44 liters of gas were released, determine

When zinc dissolves in hydrochloric acid, 13.44 liters of gas were released, determine 1) the mass of reacted zinc 2) the mass of the formed salt

Let’s implement the solution:

In accordance with the condition of the problem, we write down the equation of the process:
Zn + 2HCl = ZnCl2 + H2 – OBP, hydrogen is evolved;

Let’s make the calculations:
M (Zn) = 65.3 g / mol;

M (ZnCl2) = 136.3 g / mol.

Proportion:
1 mol of gas at normal level – 22.4 liters;

X mol (H2) – 13.44 liters from here, X mol (H2) = 1 * 13.44 / 22.4 = 0.6 mol.

We find the mass of metal, salt:
m (Zn) = Y * M = 0.6 * 65.3 = 39.18 g;

m (ZnCl2) = Y * M = 0.6 * 136.3 = 81.96 g

Answer: the obtained zinc chloride salt weighing 81.96 g, the mass of zinc is 39.18 g