When zinc interacts with hydrochloric acid, 280 ml of hydrogen will be released.

When zinc interacts with hydrochloric acid, 280 ml of hydrogen will be released. Determine the mass of consumed zinc and zinc chloride formed.

Metallic zinc is actively dissolved in hydrochloric acid to form a water-soluble salt.

The chemical reaction is described by the following equation:

Zn + 2HCl → ZnCl2 + H2;

Let’s calculate the chemical amount of hydrogen.

To do this, we divide its volume by the standard volume of 1 mole of gas, which is 22.4 liters.

N H2 = 0.28 / 22.4 = 0.013 mol;

To obtain this amount of hydrogen, it is required to dissolve the same amount of metallic zinc.

Let’s calculate the weight of 0.013 mol of zinc. For this purpose, we multiply the molar amount of zinc by its molar weight.

M Zn = 65 grams / mol;

m Zn = 0.013 x 65 = 0.845 grams;

Similarly, we find the weight of 0.013 mol of zinc chloride.

M ZnCl2 = 65 + 35.5 x 2 = 136 grams / mol;

m ZnCl2 = 0.013 x 136 = 1.768 grams;