When zinc is treated with sulfuric acid, hydrogen was released in an amount of 2.5 mol

When zinc is treated with sulfuric acid, hydrogen was released in an amount of 2.5 mol, calculate the masses of zinc and sulfuric acid required for this.

Zinc metal is converted to zinc sulfate.

Zn + H2SO4 = ZnSO4 + H2;

N H2 = 56 / 22.4 = 2.5 mol;

To obtain this amount of hydrogen, 2.5 mol of zinc must be dissolved.

Let’s calculate the weight of zinc. To this end, we multiply the amount of substance by the weight of 1 mole of metal.

m Zn = 2.5 x 65 = 162.5 grams;

To get this amount of hydrogen, you need to take 2.5 mol of sulfuric acid.

Let’s calculate its weight.

M H2SO4 = 98 grams / mol;

m H2SO4 = 2.5 x 98 = 245 grams;



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