Where is more nitrogen: In 100 g of calcium nitrate Ca (NO3) 2 or in 100 g of ammonium nitrate NH4NO3?

Given:
m (Ca (NO3) 2) = 100 g
m (NH4NO3) = 100 g

To find:
where is more than N -?

Decision:
1) M (Ca (NO3) 2) = Mr (Ca (NO3) 2) = Ar (Ca) * N (Ca) + Ar (N) * N (N) + Ar (O) * N (O) = 40 * 1 + 14 * 2 + 16 * 3 * 2 = 164 g / mol;
M (NH4NO3) = Mr (NH4NO3) = Ar (H) * N (H) + Ar (N) * N (N) + Ar (O) * N (O) = 1 * 4 + 14 * 2 + 16 * 3 = 80 g / mol;
2) n (Ca (NO3) 2) = m (Ca (NO3) 2) / M (Ca (NO3) 2) = 100/164 = 0.6 mol;
3) n (N in Ca (NO3) 2) = n (Ca (NO3) 2) * 2 = 0.6 * 2 = 1.2 mol;
4) n (NH4NO3) = m (NH4NO3) / M (NH4NO3) = 100/80 = 1.25 mol;
5) n (N in NH4NO3) = n (NH4NO3) * 2 = 1.25 * 2 = 2.5 mol;
6) n (N in NH4NO3)> n (N in Ca (NO3) 2).

Answer: The amount of N in NH4NO3 is greater than in Ca (NO3) 2.