Which boat – weighing 150 kg or 300 kg – when jumping from it, a person moves backward at a higher speed?

m1 = 150 kg.

m2 = 300 kg.

V1 “/ V2” -?

When a person jumps from a boat, the law of conservation of momentum is valid.

We will assume that in two cases a person jumps with the same mass m and with the same speed V.

m1 * V1 “= m * V.

The speed of the smaller boat after the jump will be determined by the formula: V1 “= m * V / m1.

m2 * V2 “= m * V.

The speed of the larger boat after the jump will be determined by the formula: V2 “= m * V / m2.

V1 “/ V2” = m * V * m2 / m1 * m * V = m2 / m1.

V1 “/ V2” = 300 kg / 150 kg = 2.

Answer: after the jump, a boat with a mass of m1 = 150 kg will move at a speed 2 times greater than a boat with a mass of m2 = 300 kg.



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