Which volume of hydrogen can be obtained by exposure to 0.2 mol of zinc in a solution of sulfuric acid

Given:
n (Zn) = 0.2 mol

To find:
V (H2) -?

1) Zn + H2SO4 => ZnSO4 + H2 ↑;
2) n (H2) = n (Zn) = 0.2 mol;
3) V (H2) = n * Vm = 0.2 * 22.4 = 4.48 liters.

Answer: The volume of H2 is 4.48 liters.



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