Why can’t the electronic formula of aluminum be Al 2s22p1?

Explanation of the solution to the problem: the charge of an aluminum atom is +13 (its serial number), this indicates that there are 13 electrons in the aluminum atom, respectively, if we write out the electronic configuration, but we get the following: 1s ^ 2 2s ^ 2 2p ^ 6 3s ^ 2 3p ^ 1. In the sum, the numbers in the power should equal the total number of electrons in the atom.

In addition, the aluminum atom is in the 3rd period, which means it has 3 electronic levels, that is, the outer level is designated as follows: 3s ^ 2 3p ^ 1.

If the electronic configuration of an atom ends with 2s ^ 2 2p ^ 1, then this is an atom located in the 2nd period in the 3rd group (because the number of electrons on the outer level is 3).