Why is the oxidation state S +4 in the CaSO3 compound?
| November 17, 2020 | education
Let the oxidation state of sulfur be X, then:
+ 2 + X + 3 * -2 = 0 (because the molecule is neutral)
2 + X-6 = 0
X = 6-2
X = 4
Therefore, the oxidation state of sulfur is +4
Well, or if you look at the structure:
Ca – S – 3O
3 bonds go to oxygen and one to calcium. Therefore, 4 electrons are displaced.
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