Will a body with a mass of 100 kg and a volume of 0.2 m3 float on the surface of the water or sink?

m = 100 kg.

g = 9.8 m / s2.

V = 0.2 m3.

ρ = 1000 kg / m3.

Farkh -?

Fт -?

Two forces act on a body in a liquid: the force of gravity Ft, directed vertically downward, and the buoyancy force of Archimedes Farkh, directed vertically upward.

The force of gravity is determined by the formula: Ft = m * g, where m is the mass of the body, g is the acceleration of gravity.

The buoyancy force of Archimedes is determined by the formula: Farch = ρ * g * V. Where ρ is the density of the liquid in which the body is immersed, g is the acceleration of gravity, V is the volume of the immersed part of the body in the liquid.

Ft = 100 kg * 9.8 m / s2 = 980 N.

Farch = 1000 kg / m3 * 9.8 m / s2 * 0.2 m3 = 1960 N.

Since Farkh> Ft, the body will float to the surface of the water.

Answer: the body will float on the surface of the water.