Will one pack of 200 g of soda be enough to dissolve 500 g of battery sulfuric acid?

Given:
m (Na2CO3) = 200 g
m (H2SO4) = 500 g

To find:
Is there enough Na2CO3 -?

Decision:
1) Na2CO3 + H2SO4 => Na2SO4 + CO2 + H2O;
2) M (Na2CO3) = Mr (Na2CO3) = Ar (Na) * N (Na) + Ar (C) * N (C) + Ar (O) * N (O) = 23 * 2 + 12 * 1 + 16 * 3 = 106 g / mol;
M (H2SO4) = Mr (H2SO4) = Ar (H) * N (H) + Ar (S) * N (S) + Ar (O) * N (O) = 1 * 2 + 32 * 1 + 16 * 4 = 98 g / mol;
3) n (Na2CO3) = m (Na2CO3) / M (Na2CO3) = 200/106 = 1.9 mol;
4) n (H2SO4) = m (H2SO4) / M (H2SO4) = 500/98 = 5.1 mol;
5) n (Na2CO3) <n (H2SO4).

Answer: Na2CO3 is not enough.