Will there be enough energy released during the Baikal cooling by 10 degrees to form a hurricane?

Will there be enough energy released during the Baikal cooling by 10 degrees to form a hurricane? The volume of Lake Baikal is 23,600 km ^ 3, the heat capacity of water is 4.2 kJ / (kg * K), the energy of the hurricane is 6 * 10 ^ 19 J.

In order for the possibility of hurricane formation to arise when Baikal cools down, the following inequality must be fulfilled: Qу ≤ Qb; Qу ≤ Sv * m * Δt and Qу ≤ Sv * ρw * V * Δt.

Constants and variables: Qу – hurricane energy (Qу = 6 * 10 ^ 19 J); Sv – specific heat capacity of water (according to the condition Sv = 4.2 kJ / (kg * K) = 4.2 * 10 ^ 3 J / (kg * K)); ρw is the density of water in Baikal (ρw = 1000 kg / m3); V is the volume of Lake Baikal (V = 23600 km3 = 23600 * 10 ^ 9 m3); Δt – temperature change (Δt = 10 ºС).

Calculation: Qу ≤ Sv * ρw * V * Δt.

6 * 10 ^ 19 ≤ 4.2 * 10 ^ 3 * 1000 * 23600 * 10 ^ 9 * 10.

6 * 10 ^ 19 ≤ 99.12 * 10 ^ 19 (correct).

Answer: The energy released during the cooling of Baikal by 10 ºС will be enough for the formation of a hurricane.