Wire stiffness 100 N / m, what is the weight of the weight suspended from the wire if it is extended by 5 mm?

Given:
k = 100 N / m
x = 5 mm = 0.005m
g = 10 m / s
Find: m -?
Decision:
m = kx / g
m = 100 * 0.005 / 10 = 0.05 kg
Answer: The weight of the load suspended from the wire is 0.05 kg.



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