With a monatomic ideal gas, a cyclic process takes place, inlet of which a gas of 5 kJ does work. What kind of heat will the gas receive?

The data are not complete, because we only know the work (equal to 5 * 10 ^ 3j – this is in the SI system), according to the 1 law of thermodynamics ∆U = Q + A -> Q = ∆u-A. ∆U = 3 / 2RT – for a monatomic ideal gas. Most likely, a drawing was also given, from which it was necessary to determine T.



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