With a uniform increase in current from 0 to 6 A for 0.5 s, an EMF of self-induction arises in the coil

With a uniform increase in current from 0 to 6 A for 0.5 s, an EMF of self-induction arises in the coil, equal in modulus to 12 V. What is the inductance of the coil?

Initial data: current strength increases evenly; I1 (initial current in the coil) = 0 A; I2 (final current) = 6 A; t (duration of current rise in the coil) = 0.5 s; ε (EMF of self-induction) = 12 V.
We express the inductance of the coil from the formula: ε = | L * ΔI / Δt | = | L * (I2 – I1) / Δt |, whence L = ε * Δt / (I2 – I1).
Calculation: L = 12 * 0.5 / (6 – 0) = 1 H.
Answer: The inductance of the coil is 1 H.