With a uniform lifting of the load by 10 m, a work of 1 kJ was performed.

With a uniform lifting of the load by 10 m, a work of 1 kJ was performed. What is the weight of the load? What is its mass?

Data: m (mass of evenly lifted load) = 10 m; A (perfect work) = 1 kJ (1000 J).

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Calculate the weight of the lifted load: A = F * S = P * h and P = A / h = 1000/10 = 100 N.

2) Determine the mass of the cargo: m = P / g = 100/10 = 10 kg.

Answer: An evenly lifted load has a weight of 100 N and a mass of 10 kg.