With a uniform movement of a wooden plank with a weight of 2 kg on the table, the dynamometer shows

With a uniform movement of a wooden plank with a weight of 2 kg on the table, the dynamometer shows a force of 9 N. Determine the coefficient of friction of the plank on the table?

Data: uniform movement; m (weight of a wooden board with a weight) = 2 kg; F (applied force) = 9 N.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

To determine the coefficient of friction of the taken plank on the table, we will use the formula: m * a = F – Ftr = 0; F = Ftr = μ * m * g, whence μ = F / (m * g).

Calculation: μ = 9 / (2 * 10) = 0.45.

Answer: The coefficient of friction of the taken plank on the table is 0.45.