With a uniform vertical lift of a body weighing 100 kg, a work of 5000 J was performed.

With a uniform vertical lift of a body weighing 100 kg, a work of 5000 J was performed. To what height was the load lifted?

To determine the height of a uniformly lifted load, we use the formula: A = ΔEp = m * g * h and h = A / (m * g).

Variables and constants: A – perfect work (A = 5000 J); m is the mass of the cargo (m = 100 kg); g – acceleration due to gravity (g ≈ 10 m / s2).

Let’s calculate: h = A / (m * g) = 5000 / (100 * 10) = 5 m.

Answer: The load was lifted to a height of 5 m.