With a voltage of 110 V at the terminals of the resistor, the current in it is 4 A.

With a voltage of 110 V at the terminals of the resistor, the current in it is 4 A. When the voltage across the resistor is increased to 220 V, the current will become equal to?

Given: U1 (initial voltage at the terminals of the resistor taken) = 110 V; I1 (initial amperage) = 4 A; U2 (voltage boost) = 220 V.

We express the increased current in the resistor from the equality: U1 / I1 = R (constant resistance of the resistor) = U2 / I2 and I2 = U2 * I1 / U1.

Calculation: I2 = 220 * 4/110 = 8 A.

Answer: When the voltage increases to 220 V, the desired current strength in the resistor will increase to 8 A.



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