With a voltage of 16v, a current of 2A flows through it. What current will pass through the resistor

With a voltage of 16v, a current of 2A flows through it. What current will pass through the resistor if the voltage is reduced by 2 times?

According to Ohm’s law for a section of the circuit:
I = U / R.
Let us express from this expression, resistance:
R = U1 / I1.
Substitute the numerical values:
R = U1 / I1 = 16/2 = 8 ohms.
I2 = U2 / R.
Substitute the numerical values:
I2 = U2 / R = 8/8 = 1 A.
Answer: current strength 1 A.



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