With an experimental determination of the acceleration of free fall, the student in 5 minutes. counted 150 oscillations

With an experimental determination of the acceleration of free fall, the student in 5 minutes. counted 150 oscillations of the pendulum. What value of acceleration did he get if the length of the pendulum is 1 m?

Data: t (duration of the experiment) = 5 min (in SI t = 300 s); n (number of counted oscillations) = 150 oscillations; l (length of the pendulum used) = 1 m.

We express the value of free fall acceleration obtained by the student from the equality: t / n = T = 2 * Π * √ (l / g), whence l / g = t ^ 2 / (4 * Π ^ 2 * n ^ 2) and g = l * 4 * Π ^ 2 * n ^ 2 / t ^ 2.

Let’s perform the calculation: g = 1 * 4 * 3.14 ^ 2 * 150 ^ 2/300 ^ 2 = 9.8596 m / s2.

Answer: The student received the value of free fall acceleration 9.8596 m / s2.