With an increase in the force acting on the body by 6N, the acceleration increased threefold.

With an increase in the force acting on the body by 6N, the acceleration increased threefold. The initial strength value is?

F2 = F1 + 6 Newton – the force acting on the body was increased by 6 Newton;

a2 = 3 * a1 – with an increase in force, the acceleration of the body increased 3 times.

It is required to determine F1 (Newton) – the initial value of the force.

Let m be the mass of the body. Then from Newton’s second law we have:

m = F1 / a1 (1);

m = F2 / a2 (2).

That is, we have the following equality:

F1 / a1 = F2 / a2. Taking into account the condition of the problem, we get:

F1 / a1 = (F1 + 6) / (3 * a1);

F1 = (F1 + 6) / 3;

3 * F1 = F1 + 6;

3 * F1 – F1 = 6;

2 * F1 = 6;

F1 = 6/2 = 3 Newton.

Answer: the initial value of the force is 3 Newton.