With an increase in the oscillation period 2 times, the oscillation frequency?
| April 11, 2021 | education
Given:
T1 is the initial period of fluctuations;
T2 = T1 * 2 – the oscillation period was doubled.
It is required to determine v2 / v1 – how the oscillation frequency will change when the oscillation period changes.
The period and frequency of oscillations are related to each other by the following formula:
v = 1 / T.
Then, the oscillation frequency in the first case will be equal to:
v1 = 1 / T1.
The oscillation frequency in the second case will be equal to:
v2 = 1 / T2.
v2 / v1 = (1 / T2) / (1 / T1) = T1 / T2 = T1 / (2 * T1) = 1/2, that is, will decrease by 2 times.
Answer: the vibration frequency will decrease by 2 times.
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