With an initial speed of 18 km / h and moving uniformly, the tram covered 125 meters

| August 15, 2021 | education

With an initial speed of 18 km / h and moving uniformly, the tram covered 125 meters in 10 seconds. What speed he gained at the end of the journey.

To begin with, let’s write down the formula by which you can find the speed of uniformly accelerated movement: S = t * (Vo + V) / 2.
S – the path traveled by the tram; t is the time during which it accelerated; Vo is the initial speed of the tram; V – speed at the end of the path – (our desired value). To make it easier, we first express: Vo + V, it will be equal to the ratio 2S / t. Now you can express the desired value, that is: V = 2S / t-Vo. Let’s transform and find the speed, it will be equal to: 250 / 10-5, we will reduce and get 25-5 = 20 (m / s). Since, according to the condition, the speed is given in km / h, then we express the speed in km / h: 20 * 3.6 = 72 (km / h)



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