With an initial speed of 36 km / h, the trolleybus covered a distance of 80 km in 10 seconds. With what acceleration

| August 9, 2021 | education

With an initial speed of 36 km / h, the trolleybus covered a distance of 80 km in 10 seconds. With what acceleration did the trolleybus move and what speed it acquired at the end of the route

V0 = 36 km / h = 10 m / s.

t = 10 s.

S = 80 km = 80,000 m.

a -?

V -?

We will consider the movement of the trolleybus during acceleration to be uniformly accelerated. When driving with constant acceleration, the trolleybus path S is expressed by the formula: S = V0 * t + a * t ^ 2/2.

The trolleybus acceleration a is expressed by the formula: a = 2 * (S – V0 * t) / t2.

a = 2 * (80,000 m – 10 m / s * 10 s) / (10 s) ^ 2 = 1598 m / s2.

The trolleybus speed V is expressed by the formula: V = V0 + a * t.

V = 10 m / s + 1598 m / s2 * 10 s = 15990 m / s.

We see that the acceleration and speed of the trolleybus have no real values. An error was made in the problem statement.

Answer: a = 1598 m / s2, V = 15990 m / s.



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