With how many grams of sulfuric acid can sodium oxide weighing 6.2 g react?

| June 9, 2021 | education

Since sulfuric acid is dibasic and the condition does not say anything about the reaction product, it is necessary to consider 2 cases: 1) the formation of an average salt of sodium sulfate under the action of an equimolar amount of acid and 2) the formation of an acid salt of sodium hydrogen sulfate in an excess of acid.

Let’s find the amount of sodium oxide substance:

v (Na2O) = m (Na2O) / M (Na2O) = 6.2 / 62 = 0.1 (mol).

1) Formation of sodium sulfate:

Na2O + H2SO4 = Na2SO4 + H2O

According to the reaction equation, 1 mol of Na2O reacts with 1 mol of H2SO4, therefore:

v (H2SO4) = v (Na2O) = 0.1 (mol).

Thus, the mass of sulfuric acid required for the reaction:

m (H2SO4) = v (H2SO4) * M (H2SO4) = 0.1 * 98 = 9.8 (g).

2) Formation of sodium hydrogen sulfate:

Na2O + 2H2SO4 = 2NaHSO4 + H2O

According to the reaction equation, 1 mol of Na2O reacts with 2 mol of H2SO4, therefore:

v (H2SO4) = v (Na2O) * 2 = 0.1 * 2 = 0.2 (mol).

Thus, the mass of sulfuric acid required for the reaction:

m (H2SO4) = v (H2SO4) * M (H2SO4) = 0.2 * 98 = 19.6 (g).



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.