With isobaric expansion, the gas volume increased from 4 to 16 m3. What was the initial

With isobaric expansion, the gas volume increased from 4 to 16 m3. What was the initial temperature if the final one was 800K.

Let us briefly write down the condition of the problem.

Given:

V1 = 4 m ^ 3;

V2 = 16 m ^ 3;

T2 = 800 K,

need to find T1 -?

Solution:

Let us apply the equality for the isobaric process:

V1 / T1 = V2 / T2.

For a gas of a given mass, the ratio of volume to temperature is a constant number, provided that the gas pressure does not change.

Let us express T1 from the formula using identical transformations:

T1 = (V1 * T2) / V2.

It remains for us to substitute the values into the formula and perform calculations:

T1 = (4 * 800) / 16 = 200 K.

Answer T1 = 200 K initial temperature.