With lactic acid fermentation, 144 kg of glucose received 120 kg of lactic acid. What is the mass fraction

| February 23, 2021 | education

With lactic acid fermentation, 144 kg of glucose received 120 kg of lactic acid. What is the mass fraction of the yield of lactic acid from the theoretically possible.

Let’s find the amount of the substance С6Н12О6.

n = m: M.

M (C6H12O6) = 180 kg / kmol.

n = 144 kg: 180 kg / kmol = 0.8 kmol.

Let’s find the quantitative ratios of substances.

C6H12O6 → 2 CH3CHONSOOH.

For 1 kmol of C6H12O6 there is 2 kmol of CH3CHONSOON.

The substances are in quantitative ratios of 1: 2.

The amount of the СН3СНОНСООН substance is 2 times more than the amount of the C6Н12O6 substance.

n (CH3CHONSOOH) = 2n (C6H12O6) = 0.8 × 2 = 1.6 kmol.

Let’s find the mass СН3СНОНСООН.

M (CH3CHONSOON) = 90 kg / kmol.

m = n × M.

m = 90 kg / kmol × 1.6 kmol = 144 kg.

We received 144 kg according to calculations. The product yield according to the condition of the problem is 120 kg.

144 kg – 100%,

120 kg – x%.

X = (120 kg × 100%): 144 kg = 83.33%.

Answer: 83.33%.



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