With prolonged heating of copper nitrite (2) weighing 20.2 g, copper oxide (2) weighing 7.6 g

With prolonged heating of copper nitrite (2) weighing 20.2 g, copper oxide (2) weighing 7.6 g was obtained. Determine the yield of the reaction product.

Given:
m (Cu (NO3) 2) = 20.2 g
m pract. (CuO) = 7.6 g

To find:
η (CuO) -?

1) 2Cu (NO3) 2 => 2CuO + 4NO2 + O2;
2) n (Cu (NO3) 2) = m / M = 20.2 / 188 = 0.11 mol;
3) n theory. (CuO) = n (Cu (NO3) 2) = 0.11 mol;
4) m theor. (CuO) = n * M = 0.11 * 80 = 8.8 g;
5) η (CuO) = m practical. * 100% / m theory. = 7.6 * 100% / 8.8 = 86.4%.

Answer: The CuO yield is 86.4%.