With the complete reduction of 48 g of iron oxide (3) with an excess of aluminum, 256 g kJ of heat was released

With the complete reduction of 48 g of iron oxide (3) with an excess of aluminum, 256 g kJ of heat was released. Determine the heat of reaction Fe2O3 + 2Al = 2Fe + Al2O3

1.Let’s find the amount of iron oxide substance.

n = m: M

M (Fe 2O3) = 56 × 2 + 16 × 3 = 160 g / mol.

n = 48 g: 160 g / mol = 0.3 mol.

2.During combustion of 0.3 mol of Fe 2O3, 256 kJ of heat is formed,

When 1 mol of Fe 2O3 is burned, Q kJ of heat is formed.

Q = (1 mol × 256 kJ): 0.3 mol = 853, 33 kJ.

Answer: Q = 853, 33 kJ.