With the decomposition of 4.2 g of sodium bicarbonate, the volume of carbon dioxide is released equal to …

To solve, we compose the equation:
2NaHCO3 = CO2 + H2O + Na2CO3 – the decomposition reaction of sodium bicarbonate occurs when heated to 60 degrees, carbon dioxide, water, sodium carbonate are released;
Let’s make calculations:
M (NaHCO3) = 83.9 g / mol;
M (CO2) = 44 g / mol.
Let us determine the amount of mol of NaHCO3 salt, if its mass is known:
Y (NaHCO3) = m / M = 4.2 / 83.9 = 0.05 mol;
X mol (CO2) – 0.05 mol (NaHCO3);
-1 mol -2 mol from here, X mol (CO2) = 1 * 0.05 / 2 = 0.025 mol.
We find the volume of carbon dioxide by the formula:
V (CO2) = 0.025 * 22.4 = 0.56 l.
Answer: during the decomposition reaction, carbon monoxide (4) with a volume of 0.56 liters is released.