With the help of a cable, a bucket was removed from a well 10 m deep. The weight of the bucket is 1.5 kg, and the mass

With the help of a cable, a bucket was removed from a well 10 m deep. The weight of the bucket is 1.5 kg, and the mass of water in the bucket is 10 kg. What is the minimum work of the rope elastic force?

To calculate the minimum work of the elastic force of the used hummock, we apply the formula: A = F * S = m * g * h = (m1 + m2) * g * h.

Constants and variables: m1 is the mass of the bucket (m1 = 1.5 kg); m2 is the mass of water in a bucket (m2 = 1.5 kg); g – acceleration due to gravity (g ≈ 10 m / s2); h – well depth (h = 10 m).

Let’s calculate: A = (m1 + m2) * g * h = (1.5 + 10) * 10 * 10 = 1150 J = 1.15 kJ.

Answer: When removing a bucket of water from the well, the minimum elastic force of the rope used was 1.15 kJ.