With the help of a crane, a load weighing 2500 kg was lifted to a height of 12 m. What kind of work is being done.

To determine the work done by the crane, we apply the formula: A = ΔEp = m * g * h.

Variables and constants: m – weight of the cargo (m = 2500 kg); g – acceleration due to gravity (g ≈ 10 m / s2); h – lifting height (h = 12 m).

Let’s calculate: A = m * g * h = 2500 * 10 * 12 = 300 kJ (300 * 10 ^ 3 J).

Answer: The work of the crane used is 300 kJ.