With the help of a crane, a load weighing 2500 kg was lifted to a height of 12 m. What kind of work is being done?

m = 25000 kg.
g = 9.8 m / s ^ 2.
h = 12 m.
hо = 0 m.
A -?
Mechanical work A, which the crane performs when lifting the load, is equal to the change in the potential energy of the load ΔEp.
ΔЕп = Еп – Епо.
The potential energy of a body raised above the ground, En, is determined by the formula: En = m * g * h. Where m – body mass, g – gravitational acceleration, h – body height above the ground
Eno = En = m * g * ho.
En = En = m * g * h.
A = ΔEp = m * g * (h – ho).
A = 25000 kg * 9.8 m / s ^ 2 * 12 m = 2940000 J = 2940 kJ.
Answer: the crane has done work A = 2940000 J = 2940 kJ.