With the help of a crane, a load with a mass of 1 t is lifted, determine the tension force of the cable at the beginning

With the help of a crane, a load with a mass of 1 t is lifted, determine the tension force of the cable at the beginning of the ascent if the load moves with an acceleration of 2 m / s.

m = 1 t = 1000 kg.

g = 10 m / s2.

a = 2 m / s2.

N -?

The load is acted upon by 2 forces: gravity Ft directed vertically downward, and the tension force of the crane cable directed vertically upward.

m * a = m * g + N – 2 Newton’s law in vector form.

For projections onto a vertical axis directed vertically upward, 2 Newton’s law will take the form: m * a = – Fт + N.

N = m * a + Fт.

The force of gravity Ft is determined by the formula: Ft = m * g.

The formula for determining the cable tension force will take the form: N = m * a + m * g = m * (a + g).

N = 1000 kg * (2 m / s2 + 10 m / s2) = 12000 N.

Answer: the tension force of the cable is N = 12000 N.



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