With the help of a crane, we lifted a load weighing 1.4 tons to a height of 40 cm. What kind of work is done in this case?

Initial data: m (mass of the load lifted by the crane) = 1.4 t (1.4 * 10 ^ 3 kg); h (lifting height) = 40 cm (0.4 m).

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

The work that is done when lifting a load is calculated by the formula: A = F * S = m * g * h = ΔEp.

Calculation: A = 1.4 * 10 ^ 3 * 10 * 0.4 = 5600 J (5.6 kJ).

Answer: When lifting a load, work of 5.6 kJ is performed.



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