With the help of a dynamometer, the student moved evenly a wooden block weighing 200 g on a horizontal board.
| June 17, 2021 | education
With the help of a dynamometer, the student moved evenly a wooden block weighing 200 g on a horizontal board. what is the coefficient of friction if the spring has a stiffness of 40 and it has lengthened by 1.5 cm.
Given: m (mass of a bar evenly moved by a dynamometer) = 200 g (in SI m = 0.2 kg); k (spring rate of the dynamometer used) = 40 N / m; Δx (spring elongation) = 1.5 cm (in SI Δx = 0.015 m).
Constants: g (acceleration due to gravity) ≈ 10 m / s2.
To find the coefficient of friction, we use the equality: F = Ffr. = Fcont; k * Δх = μ * m * g, whence μ = k * Δх / (m * g).
Calculation: μ = 40 * 0.015 / (0.2 * 10) = 0.3.
Answer: The coefficient of friction between the bar and the board is 0.3.
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