With the help of a lever, a load weighing 150 kg is lifted to a height of 40 cm. A force of 800 N

With the help of a lever, a load weighing 150 kg is lifted to a height of 40 cm. A force of 800 N is applied to the other arm of the lever. How much has the point of application of force dropped if the lever efficiency is 60%?

Data: m (weight of cargo) = 150 kg; h (lifting height) = 40 cm (in SI h = 0.4 m); F (force applied to the other arm of the lever) = 800 N; η (lever efficiency) = 60% or 0.6.

To calculate the distance to which the point of application of the force fell, we will use the formula: η = Ap / Az = m * g * h / (F * S), whence S = m * g * h / (F * η).

Let’s perform the calculation: S = 150 * 10 * 0.4 / (800 * 0.6) = 1.25 m.

Answer: The point of application of force dropped by 1.25 m.