With the help of a movable block, a load of 100 kg is lifted to a height of 10 m, while a work of 12.5 kJ

With the help of a movable block, a load of 100 kg is lifted to a height of 10 m, while a work of 12.5 kJ is performed. Determine the efficiency of such a mechanism.

The given tasks: m (mass of the load lifted with the help of the movable block) = 100 kg; h (lifting height) = 10 m; Asov. (perfect work) = 12.5 kJ (12.5 * 10 ^ 3 J).

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

The efficiency of the mechanism under consideration can be calculated by the formula: η = Ap / Asov. = ΔEp / Asov. = m * g * h / Asov.

Calculation: η = 100 * 10 * 10 / (12.5 * 10 ^ 3) = 0.8 (80%).

Answer: The efficiency of the mechanism under consideration is 80%.