# With the help of a movable block, a load weighing 45 kg was evenly lifted to a height of 2 m. To lift the load, a force of 300N

August 23, 2021 | education

| **With the help of a movable block, a load weighing 45 kg was evenly lifted to a height of 2 m. To lift the load, a force of 300N was applied to the end of the cable. What is the efficiency of the moving unit?**

To begin with, we need to find out by what formula the efficiency (efficiency) is calculated.

µ = A useful / A performed x 100%.

Now we have to find out the formulas for each of the works.

And useful = m x g x h.

And executed = F x s.

Given: m = 45 kg; h = 2 m; g (constant) = 10 m / s ^ 2; F = 300 N; s (distance traveled) = 4 m.

And useful = 45 kg x 2 m x 10 m / s ^ 2 = 900 J.

And executed = 300 N x 4 m = 1200 J.

Efficiency (µ) = 900 J / 1200 J x 100% (reduced by 300) = 3/4 x 100% = 0.75 x 100% = 75%

Answer: 75%.

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