With the help of a movable block, a load weighing 45 kg was evenly lifted to a height of 2 m. To lift the load, a force of 300N

With the help of a movable block, a load weighing 45 kg was evenly lifted to a height of 2 m. To lift the load, a force of 300N was applied to the end of the cable. What is the efficiency of the moving unit?

To begin with, we need to find out by what formula the efficiency (efficiency) is calculated.
µ = A useful / A performed x 100%.
Now we have to find out the formulas for each of the works.
And useful = m x g x h.
And executed = F x s.
Given: m = 45 kg; h = 2 m; g (constant) = 10 m / s ^ 2; F = 300 N; s (distance traveled) = 4 m.
And useful = 45 kg x 2 m x 10 m / s ^ 2 = 900 J.
And executed = 300 N x 4 m = 1200 J.
Efficiency (µ) = 900 J / 1200 J x 100% (reduced by 300) = 3/4 x 100% = 0.75 x 100% = 75%
Answer: 75%.