With the help of a movable block, a weight of 200 kg is lifted, applying a force of 1200N. What is the unit efficiency?

univerkov | September 25, 2021 | education

Task data: m (cargo weight) = 200 kg; a movable block was used to lift the load taken; F (applied force) = 1200 N.

Reference values: g (acceleration due to gravity) = 9.81 m / s2.

The efficiency of the mobile unit can be calculated by the formula: η = Ap / Az = ΔEp / (F * S) = m * g * h / (F * 2h) = m * g / 2F.

Calculation: η = 200 * 9.81 / (2 * 1200) = 0.8175 (81.75%).

Answer: The considered mobile unit has an efficiency of 81.75%.

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