With the help of a scrap 1.5 m long, a cabinet weighing 450N was lifted, which rested on it so that the shoulder

With the help of a scrap 1.5 m long, a cabinet weighing 450N was lifted, which rested on it so that the shoulder of this force was equal to 0.5 m. With what force did you have to act on the other end of the crowbar?

Task data: L (length of scrap taken) = 1.5 m; P (weight of the raised cabinet) = 450 N; l1 (distance from the cabinet to the point of support of the scrap) = 0.5 m.

The force with which we had to act on the other end of the scrap taken, we determine from the equality: P * l1 = M = F * l2 = F * (L – l1), whence F = P * l1 / (L – l1).

Calculation: F = 450 * 0.5 / (1.5 – 0.5) = 225 N.

Answer: To raise the cabinet, the other end of the scrap was acted with a force of 225 N.