With the help of an electric motor, a weight of 100 kg was lifted to a height of 3 m in 10 seconds.

With the help of an electric motor, a weight of 100 kg was lifted to a height of 3 m in 10 seconds. find the current in the motor if it worked at a voltage of 380V

To calculate the current in the electric motor, we use the equality: U * I * t (work of current) = m * g * h (work when lifting a load), from where we express: I = m * g * h / (U * t).

Variables and constants: m – weight of the cargo (m = 100 kg); g – acceleration due to gravity (g ≈ 10 m / s2); h is the height of the lifting of the load (h = 3 m); U – operating voltage (U = 380 V); t is the duration of the engine operation (t = 10 s).

Calculation: I = m * g * h / (U * t) = 100 * 10 * 3 / (380 * 10) = 0.789 A.

Answer: The current in the used motor is 0.789 A.