With the help of the mechanism, the load is evenly lifted vertically up to a height of 2m, applying a force of 500N

With the help of the mechanism, the load is evenly lifted vertically up to a height of 2m, applying a force of 500N. What kind of work does the force applied to the load perform?

h = 2 m.

F = 500 N.

g = 10 m / s2.

A -?

Mechanical work A is a scalar physical quantity, which is determined by the formula: A = F * S * cosα, where F is the force with which the body is lifted, S is the movement of the body, ∠α is the angle between the direction of action of the force F and the movement of S.

Since the force F directed vertically upward, and the displacement of the body S, also directed vertically upward ∠α = 0 °, then cos0 ° = 1.

S = h.

A = F * h.

A = 500 N * 2 m = 1000 J.

Answer: the force applied to the load performs mechanical work A = 1000 J.