With the help of the movable block we lift a load of 200 kg and apply a force of 1200 N What is the efficiency of the block?

In order to calculate the efficiency of the moving unit, we write down its formula:

η = Apl / Apl.

Let’s find the force of gravity acting on a load weighing 200 kg. It is equal to the product of the mass of the load and the acceleration of gravity:

Ftyl1 = mg = 200 kg * 10 m / s2 = 2000 N.

The movable block gives a 2-fold gain in strength:

F tie = 2F1 ->

F1 = F strand / 2 = 2000/2 = 1000 N.

Since the work is equal
A = Fs

then, substituting it into the efficiency formula, we can reduce the values of the cargo heights:

η = Apol / Acomplete = F1h / Ftighth = F1 / Ftyach = 1,000 N / 1,200 N ≈ 0.833 ≈ 83.3%.

Answer: 83.3%.