With the interaction of 560 liters of ammonia and the required amount of nitric acid, a salt with a mass of _ g can be obtained.

univerkov | December 30, 2020 | education

560 liters.- x. gram.
N.H3 + H.NO3 = NH4.NO3.
22.4 liters-80.

x grams. = 560 * 80: 22.4. = 2000 grams (salt).
Answer: 2000 grams (salt).

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