With the oxidation of 92 g of ethyl alcohol, 82 g of acetaldehyde were obtained

With the oxidation of 92 g of ethyl alcohol, 82 g of acetaldehyde were obtained, calculate the mass fraction of the yield of the reaction product.

To solve the problem, you need to write the equation:
1. С2Н5ОН + CuO = CH3 – COH + Cu + H2O – acetaldehyde obtained;
2. Calculation of molar masses of organic substances:
M (C2H5OH) = 46 g / mol;
M (C2H4O) = 44 g / mol.
3.Calculation of the number of moles of alcohol, aldehyde:
Y (C2H5OH) = m / M = 92/46 = 2 mol;
Y (C2H4O) = 2 mol.
4. Find the theoretical mass of the reaction product:
m (C2H4O) = Y * M = 2 * 44 = 88 g.
5. Let’s calculate the product yield:
W = m (practical) / m (theoretical) * 100;
W = 82/88 * 100 = 93.18%
Answer: Acetic aldehyde was obtained, the mass fraction of the yield was 93.18%.